Sorry I did not post this yesterday.

Ok so in yesterdays class we began by correcting the homework of the night before (pg 409 11-27 ALL). One of the questions we did was a#23 which gave us the length of the altitude which was 5.2 and we had to find the perimeter of the triangle.

1. Sin 60=5.2/x

2. sqrt(3)/2=5.2/x

3. xsqrt(3)/sqrt(3)=10.4/sqrt(3)

4. 10.4 sqrt(3)/3

5. Move the decimal in 10.4 2 times to the left getting 104 sqrt(3)/3

6. Divide that by 2 getting 52sqrt(3)/3

7.Multiply that by 3 that equals 6

8.6 is the length of one side

9. Multiply 6 by the 3 sides of the triangle concluding

that the perimeter=18

After we finished correcting the homework we used the rest of the class to work on out projects (due March 31)

OH don't forget that we have a quiz tomorrow (march 5,09) on

lesson 8-1: geometric mean

lesson 8-2: special right triangles

lesson 8-3: SOH, CAH, TOA